5. RELATIVISM in NEW PHYSICS
The particle moved on a screw trajectory with speed V is not relativistic object, but its components always relativistic objects, as move on orbit of this particle with speed of light.
On known expression of new physics for an electron:
_{} (5.1.1),
where _{}=1.1576 cm^{2}/sec. From (5.1) we shall determine radius of a screw trajectory of an electron, which one is gone with speed of light:
_{}386.134×10^{13} cm = 386.134 fm. (5.1.2).
From (5.1.2) completely clear there is a physical sense of value, which one official physics calls "a Compton wavelength of an electron":
_{}= 1.0545727×10^{27 }/ 9.109390×10^{28 }× 2.997924×10^{10 }= 386.1594 fm = r_{0} (5.1.3).
It appears is that minimum radius of a screw trajectory of an electron, on which one it gains speed of light and becomes relativistic, i.e. instead of Vr=const, will follow mr=const for satisfaction of a law of conservation of angular momentum.
From (5.1.3) it is possible to update value _{}=1.1576765 cm^{2}/sec for an electron. As any microparticles have an identical angular momentum on a screw trajectory _{}, for them:
_{} (5.1.4),
Therefore for them minimum nonrelativistic radius of a screw trajectory (Compton "a wavelength" for the given particle):
_{} (5.1.5).
From (5.1.5) it is visible, that "wavelength" will be received only at multiplying both parts of equality on 2_{}, thus we shall receive a wavelength de Broglie for a particle driving with speed of light. Thus, official physics does not understand, that such _{}.
Official physics considers that the relativism starts there, where the energy of a particle becomes more "rest energy". New physics agrees with this statement:
_{} (5.1.6).
Famous expression (5.1.6) anything diverse, as the sum of kinetic energy of a particle of translational and tangential motion with speed of light on a screw trajectory. I shall remind to the reader, that the actual speed of a particle, for which one forward speed is peer to speed of light, makes c_{}, but it is impossible experimentally to determine this speed, while. If to take into account, that _{}, (5.1.6) will be copied as:
_{} (5.1.7).
From (5.1.7) it is visible, that at radius of a screw trajectory the particle is less r_{0i} is in relativistic area, and radius of its screw trajectory is inversely proportional of energy. To achieve zero radius, it is necessary to impart a particle indefinitely large energy, mass of such particle too will be indefinitely large. In this connection it is possible to guess, that with increase of power of particle accelerators will open all new and new particles with increasing masses, therefore it is better to not spend for satisfaction of this curiosity money all for nothing, while the present particle accelerators and cosmic rays will suffice.
Apparently, that (5.1.6) does not approach for nonrelativistic area, since the additional energy is spent for increase of speed, instead of on increase of a particle mass. Let's show, that one more expression of official physics:
_{} (5.1.8)
Correctly for relativistic area. If the energy of a particle E_{2}>E_{1}, is possible to record, allowing, that _{}:
_{} (5.1.9).
Under the same conditions:
_{} (5.1.10).
By multiplying both parts (5.1.10) on c^{2}, we shall receive (5.1.8).
Let's put without the evidence still pair of useful ratio:
_{} (nonrelativistic area) and _{} (relativistic area) (5.1.11).
Apparently, that these ratio to equate each other it is impossible.
5.1.1. What energy corresponds to the formula E=mc^{2}
Earlier (chapter 5.1) we have shown, that the famous formula:
E = mc^{2} (5.1.1.1)
is reflection of the greatest possible kinetic energy, which one has the body moving with speed of light. It is the sum of kinetic energy of a body, moving on a screw trajectory, in a longitudinal and tangential direction. Any relation to «rest energy» it has not, therefore it is necessary always to understand mass in this formula relativistic mass, which one at low speeds can practically coincide a restmass. In this book is clear shown, that mass of any particle is determined by its components, moving with light speed, therefore even for a «fixed» particle mass always relativistic, not relativistic mass does not exist. For orthodoxes it is considered, that the formula (5.1.1.1) expresses the greatest possible total energy of a body. New physics asserts, that it is the greatest possible kinetic energy of a body, but the potential energy of a body can be significant more.
Let's consider potential energy of electrostatic interplay of a proton with a nucleus of atom.
(5.1.1.2),
where e  elementary charge, Z  nuclear charge, r  spacing interval from a proton up to center of a nucleus.
Both nuclear charge, and spacing interval from a proton up to center of a nucleus we shall express through nuclear mass.
In chapter 12 is shown, that the internal part of any nucleus represents a similarity of crystal lattice in clusters by which one there are _{} particles, therefore nuclear mass expressed through its charge will be approximately (without the registration of a defect of mass) is peer:
(5.1.1.3),
where m_{p}  mass of a proton, m_{n}  mass of a neutron.
The connection of nuclear mass with r is obvious:
(5.1.1.4),
where _{} nuclear density of matter (10^{14} g/cm^{3}).
Substituting (5.1.1.3) and (5.1.1.4) in (5.1.1.2), we shall discover:
(5.1.1.5).
Let's substitute numerical values of constants in a system CGS in the formulas (5.1.1.1) and (5.1.1.5).
E = 8.9875×10^{20}× m (5.1.1.6),
E_{e} = 2.06265×10^{10}× m^{2/3} (5.1.1.7).
Let's substitute in (5.1.1.6) mass of a proton m_{p} = 1.6726×10^{24} g, then its «rest energy» will make 1.5032×10^{3} ergs. By substituting this value in (5.1.1.7) we shall discover, what there should be a mass of a supernucleus, that the proton on its surface had potential energy of equal its «rest energy»:
m_{Z} = 1.7447×10^{9} g (5.1.1.8).
New physics guesses a capability of formation of supernuclei of mass up to 6.63×10^{34} g (chapter 29.7.1), therefore «the rest energy» under the formula (5.1.1.1) can make only insignificant part of a total energy of a particle. Here we once again can be convinced that official physics manipulates some concepts, not having clear representation that substantially is contained in these concepts. Now become clear those grandiose power phenomena on periphery by the Universe, it is impossible to explain which one outgoing from official representations, bound with the formula 5.1.1.1.
Here too it is necessary to open physical sense of «restmass» and «rest energy»:
E = m_{0}c^{2} (5.1.1.9).
In the theory of elementary particles is shown, that all they consist in the final accounting of an electronic neutrino and antineutrino having in a free condition minor mass. At formation of a particle half of obtained energy goes on increase of mass (it becomes equal «to a restmass»), and half on bond energy. Energy of connection on a virial theorem numerically will be peer to energy of universal repulsing:
E_{rep} = m_{0}c^{2}/2 (5.1.1.10),
therefore general energy will be peer (5.1.1.9). The formulas (5.1.1.9) and (5.1.1.10) are valid only for particles having a potential well of gravidynamic interplay. This potential well will be formed at interplay of components from homomatter (matter or antimatter). At formation of a particle from heteromatter (matter  antimatter) the potential well misses (photon), therefore their energy is determined by the formula (5.1.1.1) and they always movements in vacuum with speed of light.
Energy under the formula (5.1.1.9) is a latent energy of a particle, which one in any way herself does not exhibit so long as we save its integrity. Similarly intranuclear energy also is latent so long as a nucleus invariably.
5.2. Relativistic growth of a particle mass
On a figure 5.2.1 the relation of relativistic mass to a restmass of an electron is shown depending on its speed in fractions from speed of light. The full curve corresponds to the known formula of a relativity theory:
_{} (5.2.1),
the experimental points are obtained in 19011909. The graph is borrowed from the book J.B. Marion "Physics and physical world", "World", М., 1975, page 30.
Now we shall show that the real situation with relativistic growth of a particle mass is much more complex, than it is represented on a figure 5.2.1. The formula (5.2.1) is easy for receiving from the following scheme of impulses (figure 5.2.2).
This scheme is suitable for a immobile electron, which one only we are be about to move to the right on a figure. Two neutrinos on orbit of an electron everyone in mass m_{0}/2 already move with speed of light (as on orbit of any elementary particles), therefore any attempts to displace an electron result in relativistic increase m_{0}. Thus the motion of an electron as whole on a screw trajectory of any contribution in relativistic increase of mass does not give so long as radius of this trajectory will not become equal r_{0} under the formula (5.1.2). Therefore on an initial segment of the graph of a figure 5.2.1 up to forward speed of an electron _{} the formula (5.2.1) will be valid. At the indicated speed the electron becomes relativistic, since the vectorial sum to its translational and tangential velocity on a screw trajectory is peer of speed of light. This moment is indicated by a dagger on a figure 5.2.1.
Here there is an interesting collision arises. By the formula (5.2.1) to use already it is impossible, the concept any of an alteration of speed also is unsuitable in relativistic area. Therefore we shall take advantage of a ratio (5.1.8). The change of energy will formally was equally: _{}E=mV^{2} since is necessary to expend identical energy mV^{2}/2 on a translational motion and tangential. Change of mass: _{}m=mm_{0}. Then (5.1.8) will give:
_{} (5.2.2).
The obtained formula demonstrates, that when the electron on a screw trajectory becomes relativistic, the relativistic increase of mass takes place much faster that an angular momentum of an electron on a screw trajectory in 137 times more its own moment. All would be just so, if value m_{0} on precisely to the same law simultaneously did not decrease, which one assigns expression (5.2.1), i.e.:
_{} (5.2.3),
where m_{0r}  relativistic "restmass" of an electron in this area. From (5.2.3) it is visible, that in a limit, when the speed of an electron on a screw trajectory will reach speed of light, "restmass" of an electron will become zero. Physically it means, that at one revolution of an electron on a coil of a screw trajectory a neutrino inside an electron commit too one revolution, i.e. an electron always rotated to an axis of a screw trajectory by one side, as moon to the Earth. It provides a condition, that the speed of particles on orbit did not exceed speed of light. As the restmass of components of a relativistic particle becomes to equal zero point to find bond energy of a particle, it is necessary from its restmass to subtract restmasses of all components. To take into account above set up, the formula (5.2.3) should be substituted in numerator (5.2.2). Thus with increase of speed numerator will decrease, and the denominator decreases faster. After formal transformation in the total again we shall receive the formula (5.2.1), but now motion picture of a relativistic electron has become clear and the arisen collision has vanished.
When the speed of an electron becomes of equal speed of light, radius of a screw trajectory of an electron is peer on (5.1.2) 386.1594 fm. Thus the formula (5.2.1) becomes completely unsuitable for the description of motion of an electron. Really, from expression for an angular momentum of an electron in relativistic area: _{} let's discover m and we shall substitute in (5.2.1). After transformations V/c=0 or V=0, that is dispossessed of physical sense.
Again we are addressed to a figure 5.2.1. With increase of forward speed of an electron its tangential speed on coils of a screw trajectory was augmented also. When both speeds have reached value _{}, the total trajectory speed has become of equal speed of light. At increase of mass radius of the electron has decreased and here all clear. In a considered point of a figure 5.2.1 m=1.41m_{0}, V=C/1.41 is multiplied: _{} where r_{0} – 386.134 fm. At further increase of forward speed (up to 0.866×С) radius of a screw trajectory decreases in 2 times, from this value _{} goes on increase of a tangential velocity and it becomes of equal speed of light, and still _{} goes on increase of electronic mass and it becomes 2m_{0}. From this moment the increase of forward speed of an electron results in decreasing radius of a screw trajectory («wavelengths» of an electron) and applicable increase of mass mr=const. The equation (5.2.1) connections of mass of a body with its speed becomes unsuitable, and electron completely relativistic. Further more correctly to link electronic mass to its «wavelength» (energy or radius of a screw trajectory) instead of with forward speed. Thus, the area of increase of electronic mass from _{} Up to 2m_{0} is transition region from Vr=const to mr=const and it is indicated on a figure by 5.2.1. cyan colour.
At forward speed of a particle V = 0.866C it, as whole, is gone on a screw trajectory with a tangential velocity, equal speed of light, therefore its own angular momentum becomes to an equal angular momentum on a screw trajectory in not relativistic area, and the former own angular momentum becomes to equal zero point and together with it will become to equal zero point and former «restmass» m_{0}. Here we as though have recreated a particle from components with zero «restmass» therefore «new» restmass again will be peer m_{0} and the formula (5.2.1) again will become valid.
5.2.0.1. Relativistic mass macrobodies
On a figure 5.2.0.1.1 Curve 1 are demonstrated with relativistic growth of mass of a separate microparticle depending on its speed pursuant to the formula:
_{} (5.2.0.1.1).
This formula is obtained as a result of the analysis of impulses of components of elementary particle (chapter 5.2). The free elementary particle is moves on a screw trajectory in space in such a manner that the orbital plane of its components is always perpendicular to a traveling direction. It is outcome of gravidynamic selfeffect of a particle.
For «fixed» macrobody its mass is determined by the sum of weights of all particles from which one a body consists. Each of them represents components rotated with light speed around of common center of gravidynamic interaction. Half of energy of gravidynamic attraction of components at formation of a particle is spent for universal energy of a repulsion, equal m_{i}×c^{2}/2, where m_{i}  particle mass, and second half is spent for bond energy of components, which one pursuant to a virial theorem also is peer m_{i}×c^{2}/2. If now to find common energy of deleting components of each particle on perpetuity (equal energy of gravidynamic attraction) and to summarize it on all particles of a body, we shall receive the famous formula of energy of «rest» of a body: E_{0} = m_{0}c^{2}. Apparently, that at motion of macrobody to this energy it is necessary to add a kinetic energy of translational component of motion: E_{k} = mV^{2}/2 to receive relativistic energy macrobody: mc^{2}=m_{0}c^{2}+ mV^{2}/2. Then the relativistic growth of mass macrobody depending on forward speed it will be determined by the formula:
_{} (5.2.0.1.2),
the graph by which is figured (2) on a figure 5.2.0.1.1. Pay attention that the relativistic growth of mass macrobody at its speed equal speed of light can not exceed 2m_{0}. This growth will become infinite only at motion of macrobody with speed _{}. Just this speed is the greatest possible running speed of bodies. Just with this speed the photons and particles with «zero restmass» move if to add up their translational and tangential velocity on a screw trajectory. It is interesting, what the Einstein and his followers thinks in this reason?
5.2.1. Light speeds in new physics
In new physics of notions about light speeds differ from official.
In chapter 7.3 the concept of maximum speed is entered, which one exceeds speed of light slightly in vacuum, therefore sometimes it is more useful to mean just maximum speed.
In chapters 410 is shown, what the components of elementary particles move on circular orbits with light limiting speed, therefore principle of conservation of moment of momentum requires increase of a component mass with decreasing of radius of its orbit so that product m×r remained to a constant. Therefore on a circular orbit the particle can move with maximum speed. As all free bodies in the nature move on a screw trajectory, with increase of a running speed radius of this trajectory decreases, that is a reason of increase of a body mass. Apparently, that if the body could achieve limiting forward speed, radius of a screw trajectory would become peer to zero point, and mass of a body infinite. From here follows, that is impossible to achieve maximum speed at translational motion. At the same time speed of a body on a coil of a screw trajectory is the vectorial sum translational and tangential velocity and easily can overcome a boundary of maximum speed, coming nearer to value C_{}, where C  speed of light.
5.2.2. Relativistic growth of electronic mass on atomic orbit
Official physics considers the formula of relativistic growth of mass suitable for all cases. New physics has shown, that at orbital motion of an electron its speed can reach speed of light at radius of orbit around of a nucleus r_{0} = 386 fm (see chapter 5.1). At further decreasing of orbit radius the speed of an electron remains invariable, and mass grows under the formula
:_{} (5.2.2.1),
where: m  relativistic electronic mass, m_{e}  mass of a not relativistic electron, r  orbit radius.
Now it is interesting to look, what should be nuclear charge of a hydrogenlike atom, that the electron had orbit of radius 386 fm. For this purpose we shall take advantage of the formula (2.3) for radius of orbit in a ground state from chapter 2: _{}. Though it is unduly from the point of view of physical sense, we shall multiply numerator and denominator on m_{e}. Then in numerator there will be a square of angular momentum of an electron, but against mathematics we thus shall not sin:
(5.2.2.2).
From (5.2.2.2) we shall discover Z:
(5.2.2.3).
But _{}, where r_{a}  radius of first Bohr orbit, therefore:
(5.2.2.4).
By substituting in (5.2.2.4) numerical values, we shall discover Z = 137.
Thus, the relativistic growth of electronic mass on orbit of any conceivable atoms is impossible, therefore official physics makes the next error, when takes into account this growth.
Numerical concurrence of the found nuclear charge with reverse value of a fine structure constant not incidentally. The business that a running speed of an electron on orbit of the Bohr in 137 times is less than speed of light. To achieve speed of light, it is necessary radius of orbit of an electron to reduce in 137 times, then pursuant to the formula (5.2.2.2) nuclear charges need to be increased in 137 times.
Let's suspect, that we imparted to electron such large energy, that radius of a screw trajectory it has decreased that has coincided with classic radius of the electron. In this case speed of an electron, starting from radius instituted by expression (5.1.2) does not vary any more and is peer C, and for fulfilment of a law of conservation of angular momentum the product mr should remain a constant:
_{} (5.3.1),
whence:
_{}=1.0545727×10^{27}/2.81794092×10^{13}×2.997924×10^{10}=1248.314×10^{28} g (5.3.2).
Restmass of an electron m_{0}=9.109390×10^{28} g. Therefore, electronic mass on such orbit applicable orbit of elementary particles will be increased in:
m/m_{0}=137.03596 times (5.3.3),
i.e. corresponds to value, return fine structure constant (137.0359895). If (5.3.2) to translate in power units (5.609586×10^{26} MeV/g), we shall receive value of unit of a main quantum number (MQN, see elementary particles) in power expression:
12.48314×10^{26 }× 5.609586×10^{26 }= 70.02525 MeV. (5.3.4).
It is possible to count up electronic mass at reduction of radius of a screw trajectory up to r_{e}:
m = 0.5109991 × 386.1594 / 2.81794092 = 70.025281 MeV (5.3.5).
The most precise power value of unit MQN can be received, by multiplying a rest energy of an electron on reverse value of a fine structure constant 1 MQN = 70.0252673 MeV.
As the particles in a free condition have an angular momentum _{}, apparently, that the "exited" quantum conditions of the given particle will be aliquot to this value. Therefore, the energy levels of elementary particles will be aliquot 70.025 MeV or half of this value, if the orbital angular momentum any of a component is peer _{}/2.
5.4. Technique of calculation of radiuses of orbit, bond energy, magnetic moment and masses of elementary particles
How to find bond energy of a elementary particle, was set up in section 5.2, here only it is necessary to add, that in bond energy it is necessary to allow also for electrostatic interplay of components of a particle, though it by an essential image does not influence on bond energy.
The common angular momentum of a particle as a whole (main quantum number MQN) N is peer to the sum of moments of components on orbit of this particle:
_{} (5.4.1),
therefore computational mass of any particle on orbit to equal radius of an electron is peer:
m_{cal}=N×70.0252673 MeV (5.4.2).
If the value m_{cal} differs from a substantial particle mass more, than on 35 MeV, it means, that our suppositions about a constitution of a elementary particle require elaboration or insecurely is determined MQN.
Comparing a calculating value of mass with experimental value, it is possible to make conclusions about additional repulsing or attraction of components, which one augments or reduces radius of orbit and results in decreasing or increase of a real particle mass.
Radius of any elementary particle
_{} (5.4.3),
where m  experimental particle mass. If it is a restmass of a particle, (5.4.3) will give updated value of radius of orbit of components of a particle, on which one it is possible to judge interplay of these components or return substitution in (5.4.3) to find precise value of a particle mass.
Apparently, that the majority of elementary particles will have radius, close classic radius of an electron. For calculations in a microcosmos it is convenient to use unit of spacing interval: 1 fm = 10^{13 }cm and mass unit expressed in MeV: 5.609586×10^{26} MeV/g. 1 MeV = 1.60206×10^{6} ergs.
Let's substitute these values in (5.4.3) and we shall receive expression, where mass is expressed in MeV, and radius in fm, is convenient to use which one for any component of a particle or particle as a whole:
_{} (5.4.4).
Magnetic moment of particles calculate under the formula:
_{} (5.4.5),
where _{} magnetic moment in an erg×gauss^{1}, e  electric charge in units of CGSE, m  particle mass, c  speed of light. By substituting in (5.4.5) _{} for relativistic area and _{} for not relativistic area, after transformation, we shall discover expressions, which one do not depend on masses of particles:
_{} (5.4.6),
for not of relativistic particles and:
_{} (5.4.7)
for relativistic particles.
For example, for an electron in not relativistic area on (5.4.7) _{}=0.9274015×10^{20} ergs×gauss^{1}. To this value still it is necessary to add an own magnetic moment of an electron, but as the neutrino which is formed an electron relativistic, is necessary to use (5.4.7) substituting in it classic radius of an electron: _{}=0.006767576×10^{20} ergs×gauss^{1}. Piling both values, we shall receive: _{}= 0.934169×10^{20} ergs×gauss^{1}. The relation of a magnetic moment of a mobile electron to a magneton of the Bohr will be: _{}/_{} = 1.007297271. In process of increase of speed of an electron radius of a screw trajectory decreases, the own rotation a neutrino in an electron also is slowed down. At achievement of minimum not relativistic radius of a screw trajectory 386.1594×10^{13} cm for one revolution of an electron on a trajectory a neutrino it also makes one revolution, i.e. the electron is gone as a solid and the additional contribution to a magnetic moment does not introduce. Then from (5.4.7): _{}= 0.9274017×10^{20} ergs×gauss^{1}. In this case relation of a magnetic moment of an electron to a magneton of the Bohr will be: _{}/_{} = 1.0000002. Thus, the magnetic moment of an electron with increase of its speed drops and when it becomes relativistic, its magnetic moment coincides a magneton of the Bohr. At further increase of energy of an electron its radius of a screw trajectory is inversely proportional of energy, accordingly and the magnetic moment will decrease sharply. For example, at energy of an electron 70.0252673 MeV (radius of a screw trajectory is peer to classic radius of an electron), its magnetic moment on (5.4.7) will be: _{}=0.006767576×10^{20} ergs×gauss^{1}, i.e. to coincide an own magnetic moment of a mobile electron. Then the relation of a magnetic moment of such electron to a magneton of the Bohr will make: _{}/_{}=0.00729735. Thus, the magnetic moment of particles is not a constant, and varies depending on radius of a screw trajectory of a particle or radius of orbit in a structure of other particles.
The experimentally retrieved magnetic moment of an electron _{} is a little more magneton of the Bohr _{} in 1.0011616 times. Official physics considers a magnetic moment of an electron as abnormal (it should be peer to a magneton of the Bohr) and attracts for its explanation of notions about interplay of an electron with virtual particles of vacuum: "Abnormal magnetic moment of an electron. The radiospectroscopic researches have shown, that the magnetic moment of an electron is not peer accuracy to one magneton, and it is few more. The quantum electrodynamics has shown, that the increase of a magnetic moment of an electron is obliged to interplay of an electron with vacuum (physical space)". N.I. Kariakin etc., "Brief reference book on physics", "Higher School", М., 1962, page 354.
For new physics is apparent, that the electron, moved on a screw trajectory, with an angular momentum _{} will create a magnetic moment, equal magneton of the Bohr a plus a part of an own magnetic moment of an electron (with an angular momentum _{}). If the electron moved on a screw trajectory with light speed (as a photon), it would be turned to an axis of this trajectory always by one side, i.e. would move as a solid. In this case own magnetic moment of an electron would give the zero contribution to the common moment, since bladeswept by charges a neutrino the area is peer to zero point. In this case magnetic moment of an electron would be in accuracy peer to a magneton of the Bohr. As a neutrino in an electron moves with light speed, and electron on a screw trajectory with significant by smaller speed, a trajectory separate the neutrino will represent a variety of an epicycloid with bladeswept area of "electric current" _{}, instead of _{}, and common magnetic moment to correspond experimentally retrieved. This value coincides the correction of J. Schwinger to a magnetic moment of an electron: (_{}/2_{})_{}.
If we mechanically have added up a magnetic moment of an electron on a screw trajectory with an own magnetic moment, equal _{}/137.0391=0.0072971_{}, in the total would receive the overstated common moment _{}=1.0072971_{}. By the way to tell, the magnetic moments of the majority of particles "are anomalous", for example, for a neutron and proton. And irregularity last is not stacked in theoretical notions of orthodox physics, designed for an electron, that serves endorsement of an inaccuracy them.
With a magnetic moment of an electron it is necessary to be disassembled more in detail, since the notions of new physics differ from official physics in this problem sharply. Let's consider in the beginning nonrelativistic electron. For this case we shall use the formula (4.5) on which one a magnetic moment of an electron driving on a screw line, will be:
_{} (5.4.8),
where V  tangential velocity of an electron (equal translational), C  speed of light, e  elementary charge, R  radius of a screw trajectory. An angular momentum of an electron on a screw trajectory:
_{} (5.4.9),
where m_{0}  restmass of an electron. By substituting (5.4.9) in (5.4.8), we shall discover, that the magnetic moment of an electron in this case is peer to a magneton of the Bohr:
_{} (5.4.10).
Now we shall consider a relativistic electron. For this case we shall use the formula (4.4). The similar calculations, allowing, that thus
_{} (5.4.11)
will give:
_{} (5.4.12),
i.e. the magnetic moment of a relativistic electron _{} already will depend on its mass and to decrease with increase of energy of an electron. The formula (5.4.12) can be received differently. The relativistic electron is gyrated on a screw line as a solid, making one revolution about the own axis for one revolution on a screw trajectory, because of impossibility component it a neutrino to move with superlight speed. Therefore it is possible to record for the first (outside) neutrino, allowing, that the charge a neutrino is peer e/2: _{}, where r  radius of an electron. For the second (internal) neutrino: _{}. The sum of the moments will be _{}, whence, expressing R through an angular momentum of an electron (5.4.11) we shall receive (5.4.12). It is necessary to mean, that in a relativistic electron not only the wavelength de Broglie (radius and step of a screw trajectory) decreases, but the sizes of the electron decrease also, therefore magnetic moment of a relativistic electron is not fixed value, as it is represented to official physics. Now we shall discover an own magnetic moment of a nonrelativistic electron, allowing, that a neutrino in an electron moves with speed of light:
_{} (5.4.13).
Substituting in (5.4.13) values
_{} (5.4.14)
 fine structure constant and classic radius of an electron
_{} (5.4.15),
let's discover _{}, i.e. the own magnetic moment of an electron in 137 times is less than a magnetic moment on coils of a screw trajectory. The own mechanical moment of an electron, apparently, is peer:
S_{own}= m_{0}Cr_{0} (5.4.16).
The ratio of a magnetic moment (5.4.13) to mechanical (5.4.16) will make:
_{} (5.4.17).
By substituting (5.4.15) in (5.4.13) and obtained expression for _{}_{own} in (5.4.17), we shall discover:
_{} (5.4.18).
The ratio of an own mechanical moment (5.4.18) to a mechanical moment on a screw trajectory _{} gives expression (5.4.14), that is natural. The formula (5.4.18) gives the answer to a riddle of a genesis of electric charge _{}  electric charge directly is connected to presence of an angular momentum neutrino in an electron or positron, at the end, with presence of an angular momentum the itself neutrino. Thus, the common magnetic moment of a "thermal" mobile electron equal _{}(1+_{}) = 1.007297_{} is more, than officially recognized 1.0011616_{} and obtained from the spectroscopic data (the almost relativistic electron) and decreases in inverse proportion to energy of an electron. The experimental endorsement it will deliver a modern quantum mechanics in an inconvenient situation.
5.5. Electron (positron) and neutrino
The constitution of an electron (positron) is already reviewed enough in detail. If the electron is on orbit of any particle, it saves value of an angular momentum of a mobile electron _{} and if an electron one on orbit, together with it on this orbit there is an antineutrino or neutrino for a positron (for example, neutron, muons). If radius of orbit is peer to classic radius of an electron, its mass increases up to 70.025 MeV. Thus the size of the electron on such orbit decreases in 70.0252673 / 0.5109991 = 137.0359895 times and becomes equal 2.81794092 / 137.0359895 = 0.02056351 fm. Electronic neutrino which is formed an electron exact as decrease in the sizes, and mass everyone a neutrino becomes equal 35.01263365 MeV (_{}/2). In comparison with a mobile electron and free neutrino (ground state) their condition on orbit with radius to equal classic radius of an electron is their first exited state N=1. At N=2,3,4… the electronic mass will be augmented in a number of times, aliquot 70.0252673 MeV, and mass a neutrino will be increased in a number of times, aliquot 35.01263365 MeV. As the law of conservation of angular momentum requires that the product mr should remain to a constant, the radiuses of orbits depending on MQN will be determined by expression:
_{} (5.5.1).
From (5.5.1) it is visible, that at N=0 (ground states) radius of motion of a particle indefinitely large, but at preservation of an angular momentum is (customary _{}), the running speed will be peer to zero point. At indefinitely large N (indefinitely large mass and energy of a particle) r_{N} _{}0.
The formal value MQN is easy for finding, by sectioning mass of a particle, interesting for us, (in MeV) on the power contents of unit MQN (70.0252673 MeV). If is received close to the whole value N, quantity a neutrino in a particle even, if close to halfinteger value  is odd. However, actually energy levels of particles almost never obey in accuracy to expression (5.5.1). The differences will small and be conditioned by electrostatic interplay and miscellaneous interplay homomatter (matter  matter, antimatter  antimatter) and heteromatter (matter  antimatter). Thus, the indicated interplays sliver levels of energy instituted by expression (5.5.1) on series of sublevels depending on a concrete constitution of a particle and the value N, as at miscellaneous N the components are on miscellaneous spacing interval from each other, and their interplay is not proportional to spacing interval.
As for orbital motion of a particle with speed of light:
_{} (5.5.2),
that:
_{} (5.5.3),
where m  particle mass on orbit of radius r, and m_{0} and r_{0}, accordingly, particle mass and radius of orbit of comparison, on which one these values are known or formally are determined, for example, under the formula (5.1.5). Using (5.5.3) always it is possible to introduce the indispensable corrections taking into account of a precise position of a power sublevel. For example, mass of a muon 105.658387 MeV. Through 2.19703×10^{6} sec it is disintegrated with probability about 100 % on an electron, electronic antineutrino and muonic neutrino. By sectioning mass of a muon on 70.0252673 MeV, we shall discover formal value N_{f}=1.508861. Computational mass of a muon from table 5.5.1 will be:
m_{m }= 70.0252673 + 0.25549955 + 35.01263365 = 105.2934005 MeV.
Whence calculating value MQN: N_{m} = 1.503649. In (5.5.3) it is possible to use ratio formal and calculating value MQN:
r = 2.81794092 × 1.503649 /1.508861 = 2.80820702 fm.
We have received updated radius of a muon. It slightly less than classic radius of an electron, that indicates some attraction between components of a muon. The increase of radius would indicate some repulsing. With accounting of obtained radius of orbit (5.5.3) will give value of mass of a muon precisely conterminous with experimental value. In the same way find radiuses of any other elementary particles in a state of rest. At motion of a particle, as whole radius it decreases and easily to count up it for relativistic and ultra relativistic particles.
The characteristics of an electron (positron) and neutrino are shown in table 5.5.1.
Table 5.5.1.
Particle 
Electron 
Electronic neutrino 
Muonic neutrino 
Angular momentum of a free particle 
_{} 
_{}/2×137.035989 
_{}/2 
Mass of a free particle, MeV 
0.5109991 
4.828558 eV

661.68623 eV

Mass in a structure of an electron, MeV 
 
0.25549955 
 
Mass at orbital motion with radius of an electron N=1, MeV 
70.0252673 
0.25549955 
35.01263365 
Mass at N=2, MeV 
140.0505346 
0.5109991 
70.0252673 
Radius of a free particle, fm 
2.81794092 
depends on energy 
depends on energy 
Radius of a bound particle 
Is inversely proportional to mass 
Is inversely proportional to mass 
Is inversely proportional to mass 
The notice to table 5.5.1. To find mass a free neutrino, it is necessary to take into account that they move with speed of light in a free condition then, for example, mass the electronic neutrino will be:
0.25549955 / 137.035989 × 386.134 = 4.828558×10^{6} MeV,
and mass a muonic neutrino:
35.01263365 / 137.035989 × 386.134 = 661,686230×10^{6} MeV.
Earlier was retrieved, that radius a free electronic neutrino is peer to half of radius of a screw trajectory it.
On a figure 5.5.1 the energy levels of an electron (а), muonic neutrino (b) and electronic neutrino (c) are figured depending on N.
As the angular momentum of an electron on coils of a screw trajectory can not vary  it or is, or it is not present, at superlow temperatures (or in requirements of forfeiting of an electron of its angular momentum) we should watch discontinuous jump of properties of substances one way or another bound with presence of mobile electrons. At standard temperatures of such effects it is possible to reach, depriving electrons of an opportunity to move on a circular helix, for example, in hyperfine conductors, radius which one is significant less of wave length de Broglie of an electron at given temperature. The example of such superconducting framework with a current is served a molecule of a benzol.
Superfluidity and superconductivity from a point of view of new physics have the same reason  forfeit by particles of a moment of momentum on coils of a screw trajectory.
In first case is losses of the moment atoms of helium, and in second  electrons (_{}=0). The question is who to transmit this moment.
The atoms of helium transmit to its atoms of walls of a vessel, in which one there is a fluid helium, phase change of the second kind therefore is watched and in fluid helium there are as though two fluids, for which one the motion of atoms is basic variously. In helium I they move on segments of screw lines, and in helium II  on direct. Thus, not contradicting the doublefluid model superfluidity of a modern physics, most adequate to experiments, the new physics makes the same deductions, not attracting an official quantum mechanics. The transition of fluid helium in a superfluidity state is not accompanied by heat effect (phase change of the second kind or _{}transition), since at losses by atom of helium of an angular momentum on a screw trajectory the given atom becomes "cold", but its energy is transmitted to adjacent atoms and in the whole heat effect is not watched because of the law of conservation of energy. However, as the helium in a state of superfluidity represents an intermixture "cold" (with absence for atoms of an angular momentum) and "hot" (with an angular momentum, maintained for atoms) fluid, the mechanocaloric effect is watched. At flowing out HeII from a vessel through a narrow capillary tube in a vessel temperature is increased and, on the contrary, in a place of an inflowing HeII from a capillary tube in other vessel there is a cooling. At transition of helium in a superfluidity state, its thermal conduction is incremented, approximately, in 10^{6} times and the mechanism of a thermal conduction differs from customary to many indications. This effect also is obvious: the atoms dispossessed of an angular momentum are lookalike to electrons of superconductivity.
The enunciated reason of a superfluidity of helium enables to influence this effect by the additives in fluid helium of molecules, which one as a whole or their parts would like hook a moment of momentum of atoms of helium. Apparently, what to receive effect of superfluidity at standard temperatures it is impossible, since the potential receivers of an angular momentum take it for not so much atoms, how many award with it. Apparently, only by gear transmission of atoms through channels, the diameter which one certainly is less than diameter of a screw trajectory it is possible to achieve any successes. That concerns also superconductivity in case of a motion of charged particles. In this connection there is a sense to put forward a hypothesis, according to which one in biological objects for a durable memory the insular electric currents of a superconductivity implemented at standard temperatures in molecular channels are responsible. For ^{3}He the connection between atoms is stronger, than the connection between atoms ^{4}He at the expense of a uncompensated of magnet moment of atoms, therefore losses of an angular momentum by atoms ^{3}He is impeded, since they should interact at once with many neighbors with major effective mass (on measuring a heat capacity m_{eff}=3.1m). Therefore transition temperature ^{3}He in a superfluidity state is lower (0.01 ^{0}К), than for ^{4}He (2.1 ^{0}К). For explanation of a superfluidity ^{3}He the official physics resorts to formation of superconducting pairs already from atoms ^{3}He, considering their fermions. Apparently, that at formation of superconducting pairs the system as a whole transfers in a more profitable energy state and this process should be accompanied by a heat liberation, i.e. the phase change of the first kind should be watched, that does not correspond to experimental data.
The electrons transmit it’s the moment _{} to crystal defects or atoms of "impurity", and also the atoms of the basic crystal lattice, if do not have anything applicable more. Therefore transition temperature in a superconducting state of monocrystals of pure elements is very small. Physics of a microcosm, "Soviet encyclopedia", М., 1980, page 335.
From a point of view of orthodox physics the requalification of electrons from individualistfermions (_{}=1/2) in the collective farmersbosons (_{}=0) is completely impossible while the new physics considers, that the electrons, indiscernible on an angular momentum, (for all _{}=1) are distinctive (part have _{}=1, and part _{}=0), i.e. state "of electronic gas" at a superconductivity similarly to doublefluid model of a superfluidity.
The effect of the Josephson on notions of new physics directly confirms losses by electrons of a moment of momentum in an appearance of superconductivity. The effect is watched at passage of a superconducting current through a layer of a dielectric or layer of metal in a normal state or in superconductors with waist (point contacts). If the current exceeds some critical value, there is a voltage drop U and the photons with energy h_{}=2eU are radiated. The official physics considers, that the photons are radiated by superconducting pairs of electrons, which one are excited, and then radiate, transferring in a normal state. Such notion calls severe declaiming: 1. On a segment of a voltage drop the superconductivity misses, therefore superconducting pairs on this segment miss. 2. It is vague, how two electrons of a superconducting pair simultaneously can radiate one photon with summary exuberant energy of both electrons. 3. Allowing, that distance between electrons of a superconducting pair makes 10^{4} cm, between them there is a huge amount of other electrons belonging to other pairs. In this case radiation by a given superconducting pair of a photon with energy 2eU seems even more improbable. 4. As the superconducting pairs all time fade and occur again, is not clear, how again born pair perceives an exited state previous, that in the total to accumulate exuberant energy 2eU. The new physics explains a Josephson effect simply and without inconsistencies.
The plan of effect is given in a figure 5.5.1.1, where 1  superconductor, 2  segment of normal conductance with a voltage drop on ends U. The electron in a superconducting state has not a moment of momentum _{} (is gone rectilinearly) radius of its trajectory is peer to classic radius of an electron 2.8·10^{13} cm, therefore crystal lattice of a superconductor for it is practically blank space. Let's term such electron "cold". When this electron hits on a segment of normal conductance, it gains an angular momentum _{} from ions of a crystal lattice and its trajectory becomes screw with radius 2.3·10^{8 }cm (average speed of heat motion of an electron at temperature by close to absolute zero about 500 kms/sec). Such electron we shall term "hot". Though the electrons because of minor mass practically do not import the contribution to a heat capacity of a solid body, nevertheless, on a segment of occurrence of "hot" electrons a little heat should be immersed at the expense of diminution of energy of ions. On a segment of normal conductance the electron gains energy at the expense of increase of a forward speed _{}. But the same energy it will gain and at the expense of increase of a tangential velocity on coils of a screw line. The total increase of energy at a motion in an electric field will make mV^{2} =2eU. Hitting again on a segment of superconductivity the "hot" electron again becomes "cold" at the expense of losses of an angular momentum on ions of a crystal lattice. Thus is heat stand out. Besides its exuberant energy or is radiated by a photon with energy 2eU or is diffused on ions without radiation. At transition in a superconducting state there is a paradoxical situation: than more electrical resistance of a conductor, is the more its inhomogeneity, the is more lighter to an electron to lose an angular momentum and to become "cold", therefore well conductive metals (argentum etc.) have not superconductivity. Besides the socalled isotope effect of a superconductivity is watched: _{}, where T_{k}  critical transition temperature in a superconducting state, and M  mass of an isotope. With other things being equal (in samples of isotopes of the same element) it is easier to more light ions to accept an angular momentum of an electron, than heavy, therefore formation of "cold" electrons is easier.
As the mechanism of formation of superconducting pairs contradicts bases of a quantum mechanics in a part touched of a constitution of atom, we shall analyze notions of official physics on superconducting pairs little bit more in detail. The superconducting pairs of electrons at superconductivity are stipulated by an exchange of two electrons by phonons (it is quasiparticles  as a matter of fact sound waves). Thus, the official physics separates lattice vibrations from the lattice and this fiction, any more not having physical sense, bonds electrons among themselves. How the sound waves can result in to an attraction of electrons moreover superior a longrange Coulomb repulsion? Why the exchange of phonons gives in an attraction, instead of to repulsion? The total impulse of a superconducting pair is peer to zero point. In pairs the electrons to an opposite impulse are related. How the electrons by means of phonons can be linked, if their velocity of heat motion approximately on two orders exceeds velocity of phonons  speed of sound in metal, and moves they in the counter sides? As the superconducting pairs of electrons become on notions of official physics bosons, all of them can be in an identical ground state. On this the logic a pair of Selectrons in atom too boson, therefore all electrons in atom should pairwise take a ground state that actually does not happen.
The losses by electrons of an angular momentum are accompanied also by other effects, for example, by effect Meissner  the superconductor becomes an ideal diamagnetic and the exterior magnetic field inside it misses. It is bound that the "cold" electrons ideally follow to a Lenz law and at the expense of activity of force of the Lorentz moves on a circle, compensating an external field. The "hot" electrons moves on a screw trajectory also can not completely to compensate an exterior magnetic field. At losses of an angular momentum the electrons lose at once seven degrees of freedom from 10 (see chapter "Birth and death of a photon"), therefore to return them in a normal state the energy 3.5kT_{c} is indispensable. "Existence of such slot (power in a superconductor), having at Т _{}0 breadth about 3.5kT_{c} (where T_{c}  the transition temperature in a superconducting state) gradually shrinking at temperature rise and disappearing at T_{}T_{c}, was set on sudden change of absorption far infrared (or microwave) radiation in a superconductor at that moment, when the energy of quantums of this radiation hv became to equal breadth of a slot". R. Sproul, Modern Physics, М., 1974, page 313.
The exterior magnetic field instigates acquisition by electrons of an angular momentum at the expense of force of the Lorentz and at a sufficient intensity field the superconductivity fades. Apparently, that the energy impart by an external field should make, for example: _{}, that the superconductivity has vanished. The dependence of a critical exterior magnetic field on temperature varies the same as also energy E (see, for example, Physics of a microcosm, М., 1980, page 335 and 347). It is known, that without an external field the appearance of superconductivity is not accompanied by heat effect. From a point of view of new physics it is understandable, since the electrons lost an angular momentum, transmit energy to a crystal lattice and the system as a whole does not lose and does not gain energy. The official physics here has problem, since at formation of superconducting pairs all system as a whole transfers in a more energy profitable state, that should be accompanied by a heat liberation. At presence of an exterior magnetic field the heat effect already will and should in precision correspond to additional energy E.
Here it is necessary to convert the special attention of the reader, that the current in a superconducting ring is watched without changes during a very long time. On a classic electrodynamics charge, uniformly moving on a circle should radiate electromagnetic waves and the current will be promptly stopped. Thus, the classic electrodynamics in a problem of radiation of electromagnetic waves is erroneous. The modern physics, iterating this error, negated the theory of atom of the Bohr also has gone on a way of a bedding of errors against each other.
The proton has three particles: the positron and two photons (or, that is equivalent, two positrons and electron), therefore, for a proton N=3, since on orbit each particle has an angular momentum _{}. The constitution of particles will be shown separately. Substituting in (5.4.4) values of mass of a proton m=938.2723 MeV, we shall discover its radius: r_{p} = 0.6308 fm. As radius of orbit of components of a proton was reduced as contrasted to "normal", equal classic radius of an electron at the expense of gravidynamic interplay in: 2.81794092/0.6308 = 4.46725 times, mass of these components has increased in as much times to satisfy a law of conservation of angular momentum:
70.025 × 4.46725 = 312.819 MeV (5.6.1),
and mass of a proton as a whole will be 312.819 × 3 = 938.4575 MeV, that means, that inside a proton the minor additional repulsing acts. It is conditioned by that positively charged antineutrino in photons and in a positron look to rotation axis, i.e. spacing interval between positive electric charges it is a little less. Now we can find radiuses of a positron and photon (or electron) inside a proton and, thus to update its constitution under the formulas (5.5.2) and (5.5.3).
Substituting in (5.5.3) r_{0}= 2.81794092 fm, m_{0}= 0.5109991 MeV, m= 312.819 MeV, we shall discover: r= 0.0046032 fm. Thus, radius of a positron or photon in a proton decreases in 612.17 times. In the same ratio the radiuses a neutrino which is formed a positron and a photon decrease. Thus, proton same "empty", as the Universe, galaxy, atom or we with you. At the same time huge the gravidynamic moment of a proton organizes motion of particles around (baryons) in one plane, is similar, how the gravidynamic core will forms a spiral galaxy or rotated star a flat satellite system. The ratio computational to real mass of a proton makes:
m_{p}/m=1.000198, updated radius of a proton: 1.000198×0,6308 = 0.630925 fm.
The characteristics of a proton are shown in table 5.6.1.
Table 5.6.1.
Particle 
Angular momentum of a free particle 
Mass of a free particle, MeV 
Mass in a structure of a proton, MeV (N=1) 
Mass at N=2, MeV 
Radius of a free particle, fm 
Radius of a bound particle, fm 
Proton 
_{} 
938.2723 
 
1876.5446 
0.630925 
 
Positron 
_{} 
0.5109991 
312.819 
625.638 
2.81794092 
0.0046032 
Photon 
_{} 
Depends on energy 
312.819 
625.638 
Depends on energy 
0.0046032 
The energy levels of a proton are shown on a figure 5.6.1.